math

I've scanned the internet up and down and have even tried some curve fitting, but I haven't been able to get anything useable... What I'm looking for: f(lvl) = xp required 1 - 100 2 - 380 3 - 770 4 - 1300 5 - 2150 6 - 3300 7 - 4800 8 - 6900 9 - 10000 10 - 15000

Quick guide here, I will not take into account the growth of the amount of kegs you have or hops you have in the greenhouse or pots, that is a whole other set of worms. First of all, you need to know how many kegs you need to use for the operation, Let us start with one. there are 112 days...